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Old 04-15-2007, 05:57 AM   #1
Join Date: Apr 2007
Posts: 3
Default Part 9

When I fill out the form that we have created, I input in the date 2007-04-14, but it returns back to me 0000-00-00 in the new record that appears on the table. Everything else is fine, the other fields are updated correctly. Below I have posted the code I am using, am I making any errors?

PHP Code:
require_once("Connections/connection.php"); //database connection
$data2 $_POST['data2'];
$data3 $_POST['data3'];
$data4 $_POST['data4'];
$submit $_POST['submit'];
if ($submit && $data2 && $data3 && $data4){
$query sprintf("INSERT into table1 (field2, field3, field4) values ('$data2', '$data3', 'data4')");
mysql_query($query)or die(mysql_error());
}elseif($submit) {
"You ****ing dumbass, Fill in the form COMPLETELY!";
$query sprintf("SELECT * FROM table1");
$result = @mysql_query($query);
$row mysql_fetch_array($result);
/*do {
echo $row['field3']. "<br>";
}while ($row = mysql_fetch_array($result))*/
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Untitled Document</title>
<form id="form1" name="form1" method="post" action="<?php $_SERVER['PHP_SELF']; ?>">
<table width="360" border="1" cellpadding="0">
<td><input name="data2" type="text" id="data2" /></td>
<td><input name="data3" type="text" id="data3" /></td>
<td><input name="data4" type="text" id="data4" /></td>
<td height="38" colspan="3" align="center" valign="middle">
<input type="submit" name="Submit" value="Submit" />
<input name="submit" type="hidden" id="submit" value="1" /></td>
<table width="359" height="49" border="1" cellpadding="0">
<td width="48">ID</td>
<td width="96">data2</td>
<td width="96">data3</td>
<td width="99">data4</td>
<?php do { ?>
<td><?php echo $row['field1_id']; ?></td>
<td><?php echo $row['field2']; ?></td>
<td><?php echo $row['field3']; ?></td>
<td><?php echo $row['field4']; ?></td>
<?php }while ($row = mysql_fetch_array($result)) ?>

This is what I get...
data2 data3 data4

ID data2 data3 data4 1 17 apples 2007-04-13 2 15 pears 2007-04-06 3 23 oranges 2007-04-20 4 300 peaches 2007-04-27 5 309 pears 2007-04-28 6 309 pears 2007-04-27 7 22 oranges 0000-00-00 8 22 oranges 0000-00-00 9 400 apples 0000-00-00 10 2 pears 0000-00-00 11 1 peaches 0000-00-00
larryl is offline   Reply With Quote
Old 04-15-2007, 09:33 AM   #2
davidj's Avatar
Join Date: Sep 2005
Location: The Toon (newcastle upon Tyne)
Posts: 8,256

where you have

PHP Code:
$query sprintf("INSERT into table1 (field2, field3, field4) values ('$data2', '$data3', 'data4')"); 
please look at the variable data4

you have missed the $ off the front
Would you like to learn PHP from me? Check out -> www.codezenith.co.uk
davidj is offline   Reply With Quote

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